It's definitely harder to decay the orbit into the sun directly than it is to get to escape velocity. But to play devil's advocate, there is probably a way to get them into the sun while being a similar cost to escape velocity. All you need to do is burn prograde to a super high aphelion, ride all the way out there to Pluto or whatever and then do a small retrograde burn to bring your perihelion inside the sun's photosphere. When you then get back towards the sun years later you would slam into it with a sick velocity that I think would be worth the decades-long wait.
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This definitely reads like one of my KSP exploits...
Gravity assist with one of the larger planets to make a very narrow orbit seems to be the most efficient way. But you need the planets to align correctly to have an efficient route.
"I'll launch you into the sun once there is an appropriate transfer window to Jupiter" just doesn't have the same ring to it.
I remember there was a trick where you could transfer fuel around to move your center of gravity then rotate the ship.
I scrolled down specifically looking for a KSP comment, thank you.
Alternatively you do like the Parker Solar Probe and do 7 Venus flybys, bleeding off a little speed each time with an inverse gravity assist.
Not an expert, but I've read it's easiest to use jupiter to bleed off enough velocity to fall into our sun.
Yeah it probably is, my comment was really about raw deltaV numbers without using gravity assists.
Why is that - wouldn't you be working against solar gravity? Like you don't have to get them there quickly, just launch them in some orbit that will decay and be taken in?
the issue is not counteracting gravity, the issue is decelerating enough to hit the sun
Why would an orbit decay without something to slow the spacecraft down like an atmosphere? The problem is that any object we launch from earth has a lot of orbital velocity, which makes it almost impossible to hit the sun directly, you would have to use a lot of complex gravity assists from the inner planets to take away enough momentum. Using gravity assists to accelerate outwards is much easier
I remember watching a video about that. The gist is that you have to leave earth orbit or something idk.
You're starting with the speed of the earth
Ah... centrifugal force, ofc!:-)
To escape a body of mass you need to have enogh velocity (kinetic energy) to overcome the gravitational pull of that body. You can imagine it like a ball sitting in a bowl. With little velocity it will just roll back and forth but if it's fast enough it can roll out of the bowl and escape it's influence.
That critical speed is called "escape velocity" and it depends on mass and distance from a body. The escape velocity of earth (from the surface) is about 11.2 km/s and the sun's escape velocity (from earth orbit) is about 42.1 km/s. Earth orbits around the sun at about 29.8 km/s. If you launch in the direction of Earth's orbit, you will orbit the sun already at about 41 km/s, so you "only" need 1.1 km/s more to escape the sun, too.
If you tried to reach the sun, you could launch in the opposite direction leaving you orbiting the sun at about 18.6 km/s. Since there is almost nothing in space you won't slow down from friction and the orbit won't decay. Instead you'd have to accelerate opposite the direction you're traveling. Now, calculating exactly how much you'd need to decelerate isn't trivial since you don't want a stable orbit but an elliptical orbit that just touches the sun at the closest point (perihel). I don't know how much deceleration that takes, but it's propable that it's easier than accelerating by 1.1 km/s to escape the sun.
Launching someone straight into the sun is very very expensive but doing a gravity assist around Jupiter or something to redirect your orbit into the sun is much cheaper.
I legitimately want to be cremated by the sun after I die. Doesn't matter how long it takes.
When the sun dies it will take the earth with it iirc so if you can wait until then you're good
Even with the explanations given here, it's still very counter-intuitive for me.
I think the best thing would be to cut the person in half, send one half towards the sun and the other half out of the solar system.
The issue is that you're starting from earth, and the earth already has a lot of momentum that keeps it from falling into the sun. To get an object from here to the sun you would need to counter the majority of that momentum it already has.
Newton's third law of motion clearly says that this will take exactly 0 ∆V.
Instructions unclear. I'm going to the moon on Delta IX.
(Edit: my dumbass just realized it's ∆V, as in velocity. I thought Delta 5 was the name of a type of chemical propellant. Though now that I think of it, it really should be. Damn, and I work for a space company too. At least I'm just in IT).
Launch them into Betelgeuse instead. It's a bigger target anyway.
If we're going for a bigger target, let's go all out and aim for Stephenson 2-18. Go big or go home!
If the idea is to be rid of the person completely, we don't need to fire them into the sun. Or launch them out of the solar system. They don't even need to reach earth escape velocity.
Just launch them at the sun. Use whatever method you like. Just get them high enough that after gravity starts to overpower acceleration, there is no chance for survival. Boom! No more person. For the most part.
Just launch lots of tiny bits of processed earth at them super fast. More propellant efficient and you don't have to worry that they might have packed a parachute.
You'd still be moving some 30km/s around the sun, and need to decelerate from that speed.
A bit of a woosh. He's saying you only need to throw someone off a building or out of a plane and they'll die falling to the ground. No need to leave Earth.
Does the velocity of the earth around the sun enter into it if the projectile doesn't come anywhere close to leaving earth's gravitational pull? When I said "at the sun" it was just a direction. A gesture towards the spirit of the original "into the sun." They won't reach it. They'll just be a splat mark [insert parabola math here]-ish meters away.
So you're telling me shooting a space gun at the sun will miss?
how much to put them into a space suit and a car, strap them to a rocket and then fire them into orbit around Mars ?
More than Elon had, apparently.
Ummm… quick question: Isn’t that all just a matter of timing?
The only way to be sure is to try both ways in Kerbal Space Program.
Lol, is there a version for macOS?
(Please don’t don’t downvote me, I need to use Photoshop for work)
Looks like it runs on Mac.
(Better repent and switch to Gimp on Arch /J)
Lol
Wouldn't shooting them into Jupiter be the easiest?
I'm sure I've read a few things about what an impact that big bugger has on trajectories in our solar system.
Intuitively I feel like a push towards Jupiter would be easier than a push to get all the way out of the solar system avoiding Jupiter.