this post was submitted on 17 Aug 2023
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Programming Challenges

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Easy challenges will give 1 point, medium will give 2, and hard will give 3. If you have the fastest time or use the least amount of characters you will get a bonus point (in ties everyone gets the bonus point)

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[Med] Bracket Match Generation (programming.dev)
submitted 1 year ago* (last edited 1 year ago) by Ategon@programming.dev to c/challenges@programming.dev
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Bracket Inc. wants to ship out new products using their excess brackets. They have tasked you with generating every possible assortment of brackets for some n brackets where the brackets will match

  • A bracket match is an opening and closing version of the same kind of bracket beside each other ()
  • If a bracket matches then outer brackets can also match (())
  • n will be an even number
  • The valid brackets are ()[]{}

For example for n = 4 the options are

  • ()()
  • (())
  • [][]
  • [[]]
  • {}{}
  • {{}}
  • []()
  • ()[]
  • (){}
  • {}()
  • []{}
  • {}[]
  • ({})
  • {()}
  • ([])
  • [()]
  • {[]}
  • [{}]

You must accept n as a command line argument (entered when your app is ran) and print out all of the matches, one per line

(It will be called like node main.js 4 or however else to run apps in your language)

You can use the solution tester in this post to test you followed the correct format https://programming.dev/post/1805174

Any programming language may be used. 2 points will be given if you pass all the test cases with 1 bonus point going to whoevers performs the quickest and 1 for whoever can get the least amount of characters

To submit put the code and the language you used below

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[–] brie 1 points 1 year ago

If order doesn't matter, implementations can be quickly compared with a reference implementation using diff + sort:

>> for i in 2 4 6 8; do diff -qs <(./a.out $i|sort) <(./a.out $i|sort); done
Files /dev/fd/63 and /dev/fd/62 are identical
Files /dev/fd/63 and /dev/fd/62 are identical
Files /dev/fd/63 and /dev/fd/62 are identical
Files /dev/fd/63 and /dev/fd/62 are identical
>> for i in 2 4 6 8; do diff -qs <(./a.out $i|sort) <(true $i|sort); done
Files /dev/fd/63 and /dev/fd/62 differ
Files /dev/fd/63 and /dev/fd/62 differ
Files /dev/fd/63 and /dev/fd/62 differ
Files /dev/fd/63 and /dev/fd/62 differ