this post was submitted on 31 Oct 2024
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[–] superkret@feddit.org 33 points 1 week ago (2 children)

Just divide the number into its prime factors and then check if one of them is 2.

[–] fartripper@lemmy.ml 14 points 1 week ago* (last edited 1 week ago) (1 children)

or divide the number by two and if the remainder is greater than

-(4^34)

but less than

70 - (((23*3*4)/2)/2)

then

true
[–] superkret@feddit.org 5 points 1 week ago

What if the remainder is greater than the first, but not less than the latter?

Like, for example, 1?

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