this post was submitted on 03 Oct 2024
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Zig vs Rust. Which one is going to be future?

I think about pros and cons and what to choose for the second (modern) language in addition to C.

@programming@programming.dev

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[–] TehPers 10 points 1 month ago* (last edited 1 month ago) (1 children)

I'm not going to say that C is unusable by any means (and I'm not saying you are saying that). It's a perfectly usable language. I do think that more people would benefit from exploring other options though. Programming languages are tools, not sports teams. People should familiarize themselves with many tools so they always have a good tool to use for any job.

I think a lot of people believe this because there is some truth to parts of it. I think we see languages like Rust and Zig (and others) popping up to try and solve specific problems better than others.

As for OP's post, there is no single "C successor" or anything like that. People will use the best tool they know of for the job whether that's C, Rust, C++, Zig, Python, C#, etc. Many languages will "replace" C in some projects, and at the same time, C will replace other languages in some projects (likely to a lesser extent though).

(Not /s this time)

[–] slacktoid@lemmy.ml 10 points 1 month ago (1 children)

Oh completely. C is here to stay, C has surpassed language and become protocol cause of libc being so centric to Unix like languages. But it needs to be done carefully and thoughtfully. The other languages are solving some of the pain points C has which I think a lot of people would be better off using than C.

[–] sukhmel@programming.dev 5 points 1 month ago (1 children)

Down that path C may become somewhat of an intermediate representation language for binary interfaces. No one would write it by hand, and maybe for the better

[–] bluGill@fedia.io 1 points 1 month ago

@sukhmel@programming.dev

@programming@programming.dev @modev@snac.bsd.cafe @TehPers@beehaw.org @slacktoid@lemmy.ml C is a terrible binary interface. It doesn't say who owns a pointer, or what to call to destroy it. It doesn't normally provide buffer length (even when it does there is no reason to trust it)