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issues with bash commands as variables (monero.town)

submitted 1 year ago* (last edited 1 year ago) by shortwavesurfer@monero.town to c/programming

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Any ideas? I am attempting to write a script that uses sed.

If done this way it fails

rmdec="sed 's/..................$//'"
i1xmr=$(echo "$i1p/$apiresponse*1000" |bc -l |$rmdec)

But if i do it this way it works

i1xmr=$(echo "$i1p/$apiresponse*1000" |bc -l | sed 's/..................$//')

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[–] shortwavesurfer@monero.town 1 points 1 year ago (1 children)

Hmm. I had a look at the example given. I see the idea, but would cat be the thing to use or would it be echo <<-EOF > "$file"?

[–] bizdelnick@lemmy.ml 1 points 1 year ago (1 children)

You need cat because it reads stdin and prints it to stdout. echo does not read stdin, it prints its arguments.

[–] shortwavesurfer@monero.town 1 points 1 year ago (1 children)

I have never used cat like that before. If you just ent cat abcd > file it says abcd doesnt exist but does create "file". I know you can cat contents of a file into another file but why the <<-EOF > file works is a bit beyond me.

[–] bizdelnick@lemmy.ml 1 points 1 year ago

cat does not create file, your shell does when you redirect the standard output with > file.