this post was submitted on 20 Aug 2024
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Science Memes

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[โ€“] NeatNit@discuss.tchncs.de 3 points 2 months ago (1 children)

I don't get it, and the world's quickest and last comprehensive DDG search didn't find an explanation either.

[โ€“] kogasa@programming.dev 4 points 2 months ago

It's a reach, but the Fourier transformation of a Schwarz (rapidly decaying) function is also a Schwarz function. Compact support is a strictly stronger condition than Schwarz (the function must eventually decay to 0) but doesn't have this nice property with respect to Fourier transforms, i.e. the FT of a compactly supported function is Schwarz but not necessarily compactly supported